Real Housewives of Atlanta Star Shamea Morton and Husband Gerald Mwangi's Baby Gender Revealed: It's a Girl

Updated On 20 Sep, 2018 Published On

Baby's gender has finally been revealed! It's been more than two months Shamea Morton and Gerald Mwangi announced that they are expecting their first child, and the couple has now revealed that the Real Housewives of Atlanta is pregnant with a baby girl.

The 36-year-old reality star conducted a gender reveal party on Saturday, July 21 just one day before the couple's one-year wedding anniversary- at their Georgia home, where the couple lit up the sky with pink fireworks to reveal that they will be welcoming an adorable daughter.

They celebrated the party among more than 300 guests, including Shamea's castmates Kandi Burruss, Cynthia Bailey and Porsha Williams.

Of the party, the former Atlanta Falcons cheerleader said, "We showed our 45–minute wedding video and the entire house was quiet. There were even a few tears shed when we played our vows."

Along with the fireworks display, guests enjoyed a feast consist of cupcakes, pulled pork, corn on the cob and rotisserie chicken.

Though the television actress just wanted a healthy child, she was hoping for a girl.

She exclusively told Us Weekly, "I hope she’s a mini-me. I do girls really well. I was more terrified of a boy. I’m all for the tutus and bows."

Shamea further says her husband of one year, is also pretty excited about having a daughter. She gushed, "He already calls her his princess. He’s overjoyed."

As previously reported, on Sunday, May 13, Shamea took her 36th birthday party conducted at Sage Woodfire Tavern Perimeter in Atlanta to announce her first pregnancy.

Shamea and Gerald officially became married in July 2017 in Nairobi, Kenya, after three years of dating.

For more updates, stay tuned to Frostsnow.